(x^2)+3(2x+1)=6x+5

Solution for (x^2)+3(2x+1)=6x+5 equation:

Simplifying
(x2) + 3(2x + 1) = 6x + 5
x2 + 3(2x + 1) = 6x + 5

Reorder the terms:
x2 + 3(1 + 2x) = 6x + 5
x2 + (1 * 3 + 2x * 3) = 6x + 5
x2 + (3 + 6x) = 6x + 5

Reorder the terms:
3 + 6x + x2 = 6x + 5

Reorder the terms:
3 + 6x + x2 = 5 + 6x

Add '-6x' to each side of the equation.
3 + 6x + -6x + x2 = 5 + 6x + -6x

Combine like terms: 6x + -6x = 0
3 + 0 + x2 = 5 + 6x + -6x
3 + x2 = 5 + 6x + -6x

Combine like terms: 6x + -6x = 0
3 + x2 = 5 + 0
3 + x2 = 5

Solving
3 + x2 = 5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + x2 = 5 + -3

Combine like terms: 3 + -3 = 0
0 + x2 = 5 + -3
x2 = 5 + -3

Combine like terms: 5 + -3 = 2
x2 = 2

Simplifying
x2 = 2

Take the square root of each side:
x = {-1.414213562, 1.414213562}